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bezier

0.1.0
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  • License MIT

n-degree Bezier interpolation

Package Exports

  • bezier

This package does not declare an exports field, so the exports above have been automatically detected and optimized by JSPM instead. If any package subpath is missing, it is recommended to post an issue to the original package (bezier) to support the "exports" field. If that is not possible, create a JSPM override to customize the exports field for this package.

Readme

bezier experimental

n-degree Bezier curve interpolation.

Usage

bezier

require('bezier')(points, t)

Returns the value at t for a bezier curve of points.length degrees. In other words, if you pass it a 3-element array you'll get the results of a 3-degree (quadratic) curve.

var bezier = require('bezier')
bezier([0, 1, 2], 0.5)    // 1
bezier([0, 1, 2, 3], 0.5) // 1.5

You can use a curve for each dimension to get the resulting bezier you're probably familiar with:

var canvas = document.createElement('canvas')
var ctx = canvas.getContext('2d')

var bezier = require('bezier')
var x = [0, 1, 2]
var y = [2, 1, 0]

ctx.beginPath()
ctx.strokeStyle = '#000'
for (var t = 0; t < 1; t += 0.01) {
  ctx.lineTo(bezier(x, t), bezier(y, t))
}
ctx.stroke()
ctx.closePath()

curve = require('bezier').prepare(pointCount)

Generates a function which takes pointCount number of points to draw a bezier curve. For higher values of pointCount, this function is generated on the fly such that it can run with as little overhead as possible.

It's a small trade-off in flexibility for a small benefit in performance :)

curve(points, t)

Given an array of points that is pointCount long, return the value across the curve at t.

var quadratic = require('bezier').prepare(3)
var cubic = require('bezier').prepare(4)

quadratic([0, 1, 2], 0.5) // 1
cubic([0, 1, 2, 3], 0.5)  // 1.5

// Note that these functions expect
// arrays of the correct length:
quadratic([0, 1, 2, 3], 0.5) // 1
quadratic([0, 1], 0.5)       // NaN

License

MIT. See LICENSE.md for details.