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lateration

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    • License MIT

    Calculating a position using distances from points.

    Package Exports

    • lateration

    This package does not declare an exports field, so the exports above have been automatically detected and optimized by JSPM instead. If any package subpath is missing, it is recommended to post an issue to the original package (lateration) to support the "exports" field. If that is not possible, create a JSPM override to customize the exports field for this package.

    Readme

    Lateration

    A simple (?) solution to the fairly common problem of lateration.

    Problem

    You've got three or more beacons, their distances to your device and you want to calculate the device's position.

    Theory

    Suppose we have three circles, and somewhere in their center our beacon. The radius of each circle is the (approximate) distance to the beacon. Let call the circles A, B, and C.

    Each circle's formula would look like this:

    Formula Circle

    Substracting two circles would give a linear equation, which crosses their two intersections:

    Linear Equation from Subtraction

    Calculating the intersection of two of these linear equations gives the x-value of the devices position in between the beacons.

    Calculate x-value via intersecting

    This value can then be inserted in one of the two linear equations to get the corresponding y-value.

    This process is repeated for each pair of circles and for each pair lines resulting from this circle subtraction. The resulting points are averaged.

    Installation

    npm install lateration

    Usage (ES6)

    import {
      Circle,
      Vector,
      laterate
    } from "lateration";
    
    // The beacons
    const beacons = [
      new Circle(new Vector(0, 1), 5.89),
      new Circle(new Vector(4, 7), 4.62),
      new Circle(new Vector(4, 5), 2.73)
    ];
    
    // Laterating
    const position = laterate(beacons);

    Usage (ES5)

    var lateration = require("lateration");
    var Circle = lateration.Circle;
    var Vector = lateration.Vector;
    var laterate = lateration.laterate;
    
    // The beacons
    var beacons = [
      new Circle(new Vector(0, 1), 5.89),
      new Circle(new Vector(4, 7), 4.62),
      new Circle(new Vector(4, 5), 2.73)
    ];
    
    // Laterating
    var position = laterate(beacons);

    API

    function laterate(circles)

    Takes a list of Circles and executes a lateration operation.

    If it can't generate enough lines to intersect, it will return null.

    class Vector

    A simple vector with x and y attributes

    class Circle

    Class Line

    License

    Permission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the “Software”), to deal in the Software without restriction, including without limitation the rights to use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is furnished to do so, subject to the following conditions:

    The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software.

    THE SOFTWARE IS PROVIDED “AS IS”, WITHOUT WARRANTY OF ANY KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.