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  • License MIT

a performant queue implementation in javascript

Package Exports

  • @datastructures-js/queue

This package does not declare an exports field, so the exports above have been automatically detected and optimized by JSPM instead. If any package subpath is missing, it is recommended to post an issue to the original package (@datastructures-js/queue) to support the "exports" field. If that is not possible, create a JSPM override to customize the exports field for this package.

Readme

@datastructures-js/queue

build:? npm npm npm

A performant queue implementation in javascript.

Contents

Install

npm install --save @datastructures-js/queue

require

const { Queue } = require('@datastructures-js/queue');

import

import { Queue } from '@datastructures-js/queue';

API

constructor

JS
// empty queue
const queue = new Queue();

// from an array
const queue = new Queue([1, 2, 3]);
TS
// empty queue
const queue = new Queue<number>();

// from an array
const queue = new Queue<number>([1, 2, 3]);

Queue.fromArray(elements)

JS
// empty queue
const queue = Queue.fromArray([]);

// with elements
const list = [10, 3, 8, 40, 1];
const queue = Queue.fromArray(list);

// If the list should not be mutated, use a copy of it.
const queue = Queue.fromArray(list.slice());
TS
// empty queue
const queue = Queue.fromArray<number>([]);

// with elements
const list = [10, 3, 8, 40, 1];
const queue = Queue.fromArray<number>(list);

.enqueue(element)

adds an element at the back of the queue.

params return runtime
element: T Queue<T> O(1)
queue.enqueue(10).enqueue(20);

.front()

peeks on the front element of the queue.

return runtime
T O(1)
console.log(queue.front()); // 10

.back()

peeks on the back element in the queue.

return runtime
T O(1)
console.log(queue.back()); // 20

.dequeue()

dequeue the front element in the queue. It does not use .shift() to dequeue the element. Instead, it uses a pointer to get the front element and only remove elements when reaching half size of the queue.

return runtime
T O(n*log(n))
console.log(queue.dequeue()); // 10
console.log(queue.front()); // 20

Dequeuing all elements takes O(n*log(n)) instead of O(n2) when using shift().

benchmark:

dequeuing 1 million elements in Node v12

.dequeue().shift()
~ 40 ms~ 3 minutes

.isEmpty()

checks if the queue is empty.

return runtime
boolean O(1)
console.log(queue.isEmpty()); // false

.size()

returns the number of elements in the queue.

return runtime
number O(1)
console.log(queue.size()); // 1

.clone()

creates a shallow copy of the queue.

return runtime
Queue<T> O(n)
const queue = Queue.fromArray([{ id: 2 }, { id: 4 } , { id: 8 }]);
const clone =  queue.clone();

clone.dequeue();

console.log(queue.front()); // { id: 2 }
console.log(clone.front()); // { id: 4 }

.toArray()

returns a copy of the remaining elements as an array.

return runtime
T[] O(n)
queue.enqueue(4).enqueue(2);
console.log(queue.toArray()); // [20, 4, 2]

.clear()

clears all elements from the queue.

runtime
O(1)
queue.clear();
queue.size(); // 0

Build

grunt build

License

The MIT License. Full License is here