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  • License MIT

Better binary searching

Package Exports

  • binary-search-bounds

This package does not declare an exports field, so the exports above have been automatically detected and optimized by JSPM instead. If any package subpath is missing, it is recommended to post an issue to the original package (binary-search-bounds) to support the "exports" field. If that is not possible, create a JSPM override to customize the exports field for this package.

Readme

binary-search-bounds

Binary search on arrays for ranges.

Install

npm install binary-search-bounds

API

var bounds = require("binary-search-bounds")

bounds.lt(array, y[, cmp, lo, hi])

Returns the index of the last item in the array < y

bounds.le(array, y[, cmp, lo, hi])

Returns the index of the last item in the array <= y

bounds.gt(array, y[, cmp, lo, hi])

Returns the index of the first item in the array > y

bounds.ge(array, y[, cmp, lo, hi])

Returns the index of the first item in the array >= y

bounds.eq(array, y[, cmp, lo, hi])

Returns an index of some item in the array == y.

Notes

The following comments apply to the above methods:

  • cmp is a comparison function, just like what you would pass to Array.sort()
  • y will always be the second argument passed to cmp, so you can ignore it if you are just binary searching on a predicate.
  • Assumes the array is sorted as would be the case if you called Array.sort(cmp) on it
  • If no comparison is passed, assume array is sorted in ascending order (note this is different than the semantics of Array.sort() which converts all entries to strings if you don't pass an argument)
  • lo gives a lower bound on the array index to search. If not specified defaults to 0.
  • hi gives an upper bound on the array index to search. If not specified defaults to array.length-1
  • Bouth bounds are inclusive.
  • bounds.le and bounds.lt will return lo - 1 if no element is found that ==y
  • bounds.ge and bounds.gt will return hi + 1 if no element is found that ==y
  • bounds.eq will return -1 if no element matching y is found.
  • bounds.eq will return the first found item with the given index. It can be a little faster than the other methods if you just want to find some random match and do not care where it is.

Credits

(c) 2013 Mikola Lysenko. MIT License