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Binary Search Trees

Package Exports

  • bintrees

This package does not declare an exports field, so the exports above have been automatically detected and optimized by JSPM instead. If any package subpath is missing, it is recommended to post an issue to the original package (bintrees) to support the "exports" field. If that is not possible, create a JSPM override to customize the exports field for this package.

Readme

Binary Trees Build Status

This package provides Binary and Red-Black Search Trees written in Javascript. It is released under the MIT License.

Binary Search Trees are a good way to store data in sorted order. A Red-Black tree is a variation of a Binary Tree that balances itself.

Algorithms were taken from Julienne Walker: http://eternallyconfuzzled.com/jsw_home.aspx

Trees

  • BinTree - Binary Search Tree
  • RBTree - Red-Black Tree

Quickstart

node.js:

npm install bintrees
var Tree = require('bintrees').RBTree;

var tree = new RBTree(function(a, b) { return a - b; });

tree.insert(2);
tree.insert(-3);

see examples/node.js for more info

In the browser:

<script src="/path/to/rbtree.js"></script>
<script>
    var tree = new RBTree(function(a, b) { return a - b });
    tree.insert(0);
    tree.insert(1);
</script>

see examples/client.html for more info

Constructor

Requires 1 argument: a comparator function f(a,b) which returns:

  • 0 if a == b
  • 0 if a > b

  • <0 if a < b

Methods

  • insert(item)
  • remove(item)
  • clear()
  • find(item)
  • min()
  • max()
  • each(f)
  • reach(f)
  • iterator()

See the comments inside the lib directory for more info.

Iterators

tree.iterator() will return a null-iterator. On a null iterator,

  • next() will return the first element in the tree
  • prev() will return the last element in the tree

Otherwise,

  • next() will return the next element
  • prev() will return the previous element

When iteration reaches the end, the iterator becomes a null-iterator again.

Forward iteration example:

var it=tree.iterator(), item;
while((item = it.next()) !== null) {
    // do stuff with item
}

If you are iterating forward through the tree, you can always call prev() to go back, and vice versa.