Package Exports

with

This package does not declare an exports field, so the exports above have been automatically detected and optimized by JSPM instead. If any package subpath is missing, it is recommended to post an issue to the original package (with) to support the "exports" field. If that is not possible, create a JSPM override to customize the exports field for this package.

Readme

with

Compile time with for strict mode JavaScript

Installation

$ npm install with

Usage

var addWith = require('with')

addWith('obj', 'console.log(a)')
// => ';(function (console, a) {
//       console.log(a)
//     }("console" in obj ? obj.console :
//                          typeof console!=="undefined" ? console : undefined,
//       "a" in obj ? obj.a :
//                    typeof a !== "undefined" ? a : undefined));'

addWith('obj', 'console.log(a)', ['console'])
// => ';(function (console, a) {
//       console.log(a)
//     }("a" in obj ? obj.a :
//                    typeof a !== "undefined" ? a : undefined));'

API

addWith(obj, src[, exclude])

The idea is that this is roughly equivallent to:

with (obj) {
  src
}

There are a few differences though. For starters, assignments to variables will always remain contained within the with block.

e.g.

var foo = 'foo'
with ({}) {
  foo = 'bar'
}
assert(foo === 'bar')// => This fails for compile time with but passes for native with

var obj = {foo: 'foo'}
with ({}) {
  foo = 'bar'
}
assert(obj.foo === 'bar')// => This fails for compile time with but passes for native with

It also makes everything be declared, so you can always do:

if (foo === undefined)

instead of

if (typeof foo === 'undefined')

This is not the case if foo is in exclude. If a variable is excluded, we ignore it entirely. This is useful if you know a variable will be global as it can lead to efficiency improvements.

It is also safe to use in strict mode (unlike with) and it minifies properly (with disables virtually all minification).

License

MIT